Chek the correctness of the relation, S(n(th)) = u +(a)/(2)(2n -1), where u is initial velocity, a is acceleratin and S(n(th)) is the distance travelled by the body in nth second.

The given relation is S(nth) = u +(a)/(2)(2n-1) Writing the dimensions on either side, we get L.H.S = S(nth) = ("disntance")/("time") = (L)/(T) = LT^(-1) =[M^0L^1T^(-1)] R.H.S. = u + (a)/(2)(2n-1) = LT^(-1) +LT^(-2)(T) = LT^(-1) + LT^(-1) = LT^(-1) =[M^0L^1T^(-1)]. As LHS = RHS, dimensionally Formula is correct.